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Solve the product power $\left(2\sqrt{3x-5\left(3x-14\right)}\right)^2$

Step-by-step Solution

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Final Answer

$4\left(-12x+70\right)$
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Step-by-step Solution

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The power of a product is equal to the product of it's factors raised to the same power

$2^2\left(\sqrt{3x-5\left(3x-14\right)}\right)^2$

Learn how to solve power of a product problems step by step online.

$2^2\left(\sqrt{3x-5\left(3x-14\right)}\right)^2$

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Learn how to solve power of a product problems step by step online. Solve the product power (2(3x-5(3x-14))^1/2)^2. The power of a product is equal to the product of it's factors raised to the same power. Calculate the power 2^2. Simplify \left(\sqrt{3x-5\left(3x-14\right)}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals \frac{1}{2} and n equals 2. Multiply \frac{1}{2} times 2.

Final Answer

$4\left(-12x+70\right)$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SimplifyWrite in simplest formFactorFactor by completing the squareFind the integralFind the derivativeFind 2(3x+-5(3x-14))^0.5^2 using the definitionSolve by quadratic formula (general formula)Find the rootsFind break even pointsFind the discriminant

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Plotting: $4\left(-12x+70\right)$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Power of a product

The power of a product of factors is equal to the product of each factor to the same power: $\left(b\cdot c\right)^n=b^n\cdot c^n$.

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