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Expand the integral $\int\left(2x^5-10x^3-2x^2+\frac{10}{x^2-5}\right)dx$ into $4$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int2x^5dx+\int-10x^3dx+\int-2x^2dx+\int\frac{10}{x^2-5}dx$
Learn how to solve integrals of polynomial functions problems step by step online. Integrate int(2x^5-10x^3-2x^210/(x^2-5))dx. Expand the integral \int\left(2x^5-10x^3-2x^2+\frac{10}{x^2-5}\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int2x^5dx results in: \frac{1}{3}x^{6}. The integral \int-10x^3dx results in: -\frac{5}{2}x^{4}. The integral \int-2x^2dx results in: -\frac{2}{3}x^{3}.