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Integrate the function $\frac{2x^3-4x^2-15x+5}{x^2-2x-8}$ from $1$ to $3$

Step-by-step Solution

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Final Answer

The integral diverges.

Step-by-step Solution

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Rewrite the expression $\frac{2x^3-4x^2-15x+5}{x^2-2x-8}$ inside the integral in factored form

$\int_{1}^{3}\frac{2x^3-4x^2-15x+5}{\left(x+2\right)\left(x-4\right)}dx$

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$\int_{1}^{3}\frac{2x^3-4x^2-15x+5}{\left(x+2\right)\left(x-4\right)}dx$

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Learn how to solve problems step by step online. Integrate the function (2x^3-4x^2-15x+5)/(x^2-2x+-8) from 1 to 3. Rewrite the expression \frac{2x^3-4x^2-15x+5}{x^2-2x-8} inside the integral in factored form. Expand. Divide 2x^3-4x^2-15x+5 by x^2-2x-8. Resulting polynomial.

Final Answer

The integral diverges.

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Function Plot

Plotting: $\frac{2x^3-4x^2-15x+5}{x^2-2x-8}$

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