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\frac{d}{dx}\left(x^2+y^2-4xy=1\right)

Derive the function y^2xy*-4+x^2=1 with respect to x

Answer

$2x-4y=0$

Step-by-step explanation

Problem

$\frac{d}{dx}\left(x^2+y^2-4xy=1\right)$
1

Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(-4y\cdot x+y^2+x^2\right)=\frac{d}{dx}\left(1\right)$

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Answer

$2x-4y=0$

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$\frac{d}{dx}\left(x^2+y^2-4xy=1\right)$

Main topic:

Differential calculus

Used formulas:

4. See formulas

Time to solve it:

~ 0.26 seconds