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Find the derivative of y^2xy*-4+x^2=1

\frac{d}{dx}\left(x^2+y^2-4xy=1\right)

Step by step solution

Problem

$\frac{d}{dx}\left(x^2+y^2-4xy=1\right)$

Show full step-by-step solution

Answer

$\frac{d}{dx}\left(-4y\cdot x\right)+2x=0$
$\frac{d}{dx}\left(x^2+y^2-4xy=1\right)$

Main topic:

Differential calculus

Used formulas:

3. See formulas

Time to solve it:

0.21 seconds