$\int_{\frac{1}{2}}^{\frac{3}{4}}\left(\frac{1}{x^2}\right)dx$
$-8g+15-19-13g$
$-4x-3=9$
$y^3=x-2$
$3cot^2\left(\frac{2\pi}{3}\right)$
$y'=2y-4$
$\left(x-2\right)\left(x+2\right)-\left(2x+3\right)^2$
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