$\frac{dy}{dx}=\left(1-x^2\right)y$
$3x^2-5x,\:3$
$\frac{x+1}{x^2-3x-4}$
$t^{\sqrt{3t}}$
$3x^2-6x=3$
$-9\cdot\left(-\frac{7}{3}\right)$
$\log\left(3x\right)+\log\left(x\right)=9$
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