Final Answer
$\frac{\sqrt{b^2- +a}-\sqrt{b^2-a}}{+a-a}$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Evaluate the limit $\lim_{x\to+a}\left(\frac{\sqrt{b^2-x}-\sqrt{b^2-a}}{x-a}\right)$ by replacing all occurrences of $x$ by $+a$
$\frac{\sqrt{b^2- +a}-\sqrt{b^2-a}}{+a-a}$
Final Answer
$\frac{\sqrt{b^2- +a}-\sqrt{b^2-a}}{+a-a}$