$\frac{dp}{dt}=\frac{\ln\left(t\right)}{\ln\left(p\right)}$
$csc^2\left(x\right)+3=5-csc\left(x\right)$
$9^3-s^3$
$\left(3^4.b^5\right)^2$
$100d^2-60d+9$
$p^2-1+9q^2-6pq$
$3-_{\left|-8\right|}$
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