$dx-\frac{1}{y^2+6y+13}dy=0$
$y^2+14y+28$
$y=\left(8x^3-2x\right)^3$
$3\cdot7-6\cdot5$
$-\frac{1}{x}-\frac{3}{x}$
$10^3\cdot10d^{15}$
$4\left(x-1\right)-2x\ge\frac{x}{4}-1$
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