Evaluate the limit $\lim_{x\to{inf}}\left(\frac{4x-3}{5x^2+1}\right)$ by replacing all occurrences of $x$ by $inf$
$\frac{4inf-3}{5\left(inf\right)^2+1}$
2
The power of a product is equal to the product of it's factors raised to the same power
$\frac{4inf-3}{5i^2n^2f^2+1}$
Final Answer
$\frac{4inf-3}{5i^2n^2f^2+1}$
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