$\frac{u}{\sqrt{1+u^2}\left(1-\sqrt{1+u^2}\right)}=\frac{dx}{du}\cdot\frac{1}{x}$
$20x+25c$
$8m-5-m-8$
$\left(5b^3c^3+6xy\right)\left(5b^3c^3-6xy\right)$
$\int\frac{1}{b-a}dx$
$\frac{dy}{dx}-\frac{1}{x}y=1-\frac{1}{x}$
$\int\frac{16x-8}{x^2-4}dx$
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