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Expand the integral $\int_{\frac{\pi}{8}}^{\frac{\pi}{4}}\left(1-2\sin\left(x\right)^2\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{\frac{\pi}{8}}^{\frac{\pi}{4}}1dx+\int_{\frac{\pi}{8}}^{\frac{\pi}{4}}-2\sin\left(x\right)^2dx$
Learn how to solve definite integrals problems step by step online. Integrate the function 1-2sin(x)^2 from pi/8 to pi/4. Expand the integral \int_{\frac{\pi}{8}}^{\frac{\pi}{4}}\left(1-2\sin\left(x\right)^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{\frac{\pi}{8}}^{\frac{\pi}{4}}1dx results in: \frac{\pi}{8}. The integral \int_{\frac{\pi}{8}}^{\frac{\pi}{4}}-2\sin\left(x\right)^2dx results in: -\frac{82}{333}. Gather the results of all integrals.