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# Expand the logarithmic expression $\ln\left(\frac{2+5}{2}\right)$

## Step-by-step Solution

Go!
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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Videos

$\ln\left(7\right)-\ln\left(2\right)$
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## Step-by-step Solution

Problem to solve:

$\ln\left(\frac{2+5}{2}\right)$

Specify the solving method

1

The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator

$\ln\left(2+5\right)-\ln\left(2\right)$
2

Add the values $2$ and $5$

$\ln\left(7\right)-\ln\left(2\right)$

$\ln\left(7\right)-\ln\left(2\right)$

$1.2528$
SnapXam A2

Go!
1
2
3
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Useful tips on how to improve your answer:

$\ln\left(\frac{2+5}{2}\right)$

### Main topic:

Expanding Logarithms

~ 0.02 s