Final Answer
$\frac{\left(x-2\right)^{87}}{87}+C_0$
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Step-by-step Solution
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1
The trinomial $\left(x^2-4x+4\right)$ is a perfect square trinomial, because it's discriminant is equal to zero
$\Delta=b^2-4ac=-4^2-4\left(1\right)\left(4\right) = 0$
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$\Delta=b^2-4ac=-4^2-4\left(1\right)\left(4\right) = 0$
Learn how to solve integral calculus problems step by step online. Find the integral int((x^2-4x+4)^43)dx. The trinomial \left(x^2-4x+4\right) is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial. Simplify \left(\left(x-2\right)^{2}\right)^{43} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 43.
Final Answer
$\frac{\left(x-2\right)^{87}}{87}+C_0$