$\left(x+5\right)\left(x-5\right)-25+6x^2$
$\frac{dr}{dx}+r\tan\left(x\right)=\sec\left(x\right)$
$4\:.\:-2\:+\:-54$
$125x^6y^3-8$
$4\left(3x+5\right)-13-8x$
$\left(ab^2-3cd^3\right)^2$
$\left(5x-2\right)\left(7x+6\right)$
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