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Step-by-step Solution

Find the implicit derivative $\frac{d}{dx}\left(\tan\left(-1\right)^x=\frac{1}{1+x^2}\right)$

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Answer

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Step-by-step explanation

Problem to solve:

$\frac{d}{dx}\tan\:^{-1}\left(x\right)=\frac{1}{1+x^2}$
1

Calculating the tangent of $-1$ degrees

$\frac{d}{dx}\left({\left(-\frac{31}{20}\right)}^x=\frac{1}{1+x^2}\right)$

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Answer

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$\frac{d}{dx}\tan\:^{-1}\left(x\right)=\frac{1}{1+x^2}$

Main topic:

Implicit differentiation

Time to solve it:

~ 0.02 seconds

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