** Final answer to the problem

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** Step-by-step Solution **

** How should I solve this problem?

- Choose an option
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$

Learn how to solve logarithmic equations problems step by step online.

$\log \left(\frac{x-1}{x+3}\right)=-\log \left(x\right)$

Learn how to solve logarithmic equations problems step by step online. Solve the logarithmic equation log(x+-1)-log(x+3)=-log(x). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Apply the formula: a\log_{b}\left(x\right)=\log_{b}\left(x^a\right), where a=-1 and b=10. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. Multiply both sides of the equation by x+3.

** Final answer to the problem

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