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A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$
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$x\left(x+12\right)>x^2-8x+16$
Learn how to solve problems step by step online. Solve the inequality x(x+12)>(x-4)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Multiply the single term x by each term of the polynomial \left(x+12\right). When multiplying two powers that have the same base (x), you can add the exponents. The trinomial x^2-8x+16 is a perfect square trinomial, because it's discriminant is equal to zero.