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The integral of a constant times a function is equal to the constant multiplied by the integral of the function
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$3\int_{0}^{8}\sqrt{x+1}dx$
Learn how to solve problems step by step online. Integrate the function 3(x+1)^1/2 from 0 to 8. The integral of a constant times a function is equal to the constant multiplied by the integral of the function. Apply the formula: \int\left(x+a\right)^ndx=\frac{\left(x+a\right)^{\left(n+1\right)}}{n+1}+C, where a=1 and n=\frac{1}{2}. Simplify the expression inside the integral. Evaluate the definite integral.