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Rewrite the integrand $\left(2x+\frac{-1}{x}\right)^2$ in expanded form
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$\int_{1}^{3}\left(4x^2-4+\frac{1}{x^2}\right)dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (2x+-1/x)^2 from 1 to 3. Rewrite the integrand \left(2x+\frac{-1}{x}\right)^2 in expanded form. Expand the integral \int_{1}^{3}\left(4x^2-4+\frac{1}{x^2}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{1}^{3}4x^2dx results in: \frac{104}{3}. The integral \int_{1}^{3}-4dx results in: -8.