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\frac{d}{dx}\left(y=\frac{3}{x}-\frac{2}{x^2}+\frac{2}{3x^3}\right)

Find the derivative of y=-12/(x^2)+2/(3x^3)+3/x

Answer

$0=\frac{x^{4}\left(4x^2-3x^{3}\right)-2x^{5}}{x^{9}}$

Step-by-step explanation

Problem

$\frac{d}{dx}\left(y=\frac{3}{x}-\frac{2}{x^2}+\frac{2}{3x^3}\right)$
1

Taking out the constant $3$ from the fraction's denominator

$\frac{d}{dx}\left(y=\frac{1}{3}\cdot\frac{2}{x^3}-\frac{2}{x^2}+\frac{3}{x}\right)$

Unlock this step-by-step solution!

Answer

$0=\frac{x^{4}\left(4x^2-3x^{3}\right)-2x^{5}}{x^{9}}$
$\frac{d}{dx}\left(y=\frac{3}{x}-\frac{2}{x^2}+\frac{2}{3x^3}\right)$

Main topic:

Differential calculus

Used formulas:

6. See formulas

Time to solve it:

~ 0.84 seconds