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# Integrate x^2+x-x^2 from -1 to 2

### Videos

$\frac{3}{2}$

## Step-by-step explanation

Problem to solve:

$\int_{-1}^{2}\left(x^2+x-x^2\right)dx$
1

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int_{-1}^{2} x^2dx+\int_{-1}^{2} xdx+\int_{-1}^{2}-x^2dx$
2

Take the constant out of the integral

$\int_{-1}^{2} x^2dx+\int_{-1}^{2} xdx-\int_{-1}^{2} x^2dx$

$\frac{3}{2}$
$\int_{-1}^{2}\left(x^2+x-x^2\right)dx$

### Main topic:

Integral calculus

~ 0.96 seconds