$\frac{dz}{dt}=4+z^2$
$\left(3ca+bx\right)^3$
$\int x^8\cdot\sqrt{2-x^3}dx$
$\frac{x^2+x-2}{x^2-x-2}\cdot\frac{x-2}{4x+8}$
$-5\left(\:2x\:+\:1\right)\:=\:-25$
$\int\left(5x^3+8\right)^6x^2dx$
$\frac{x}{\ln\left(x\right)}.dy-dx=0$
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