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Rewrite the expression $\frac{16x^2-48x+15}{2x^3-7x^2+3x}$ inside the integral in factored form
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$\int\frac{16x^2-48x+15}{x\left(2x-1\right)\left(x-3\right)}dx$
Learn how to solve problems step by step online. Find the integral int((16x^2-48x+15)/(2x^3-7x^23x))dx. Rewrite the expression \frac{16x^2-48x+15}{2x^3-7x^2+3x} inside the integral in factored form. Rewrite the fraction \frac{16x^2-48x+15}{x\left(2x-1\right)\left(x-3\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by x\left(2x-1\right)\left(x-3\right). Multiplying polynomials.