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\frac{d}{ds}\left(\left(s-\left(v\cdot cos\left(m\right)-1\right)\cdot t\right)^2+\left(v\cdot sin\left(m\right)\cdot t\right)^2=r^2\right)

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Final Answer

$2\left(s+t\left(-v\cos\left(m\right)+1\right)\right)\left(1-v\cos\left(m\right)+1\right)+2v^2t\sin\left(m\right)^2=0$

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Math interpretation of the question

$\frac{d}{ds}\left(\left(s-t\left(v\cos\left(m\right)-1\right)\right)^2+\left(vt\sin\left(m\right)\right)^2=r^2\right)$

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$\frac{d}{ds}\left(\left(s-t\left(v\cos\left(m\right)-1\right)\right)^2+\left(vt\sin\left(m\right)\right)^2=r^2\right)$

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Learn how to solve problems step by step online. \frac{d}{ds}\left(\left(s-\left(v\cdot cos\left(m\right)-1\right)\cdot t\right)^2+\left(v\cdot sin\left(m\right)\cdot t\right)^2=r^2\right). Math interpretation of the question. Simplify the derivative by applying the properties of logarithms. The power of a product is equal to the product of it's factors raised to the same power. Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable.

Final Answer

$2\left(s+t\left(-v\cos\left(m\right)+1\right)\right)\left(1-v\cos\left(m\right)+1\right)+2v^2t\sin\left(m\right)^2=0$

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