Final Answer
Step-by-step Solution
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Divide $6x^3+3x^2-16x-8$ by $x^2-4$
Learn how to solve integral calculus problems step by step online.
$\begin{array}{l}\phantom{\phantom{;}x^{2}-4;}{\phantom{;}6x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-4\overline{\smash{)}\phantom{;}6x^{3}+3x^{2}-16x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-4;}\underline{-6x^{3}\phantom{-;x^n}+24x\phantom{;}\phantom{-;x^n}}\\\phantom{-6x^{3}+24x\phantom{;};}\phantom{;}3x^{2}+8x\phantom{;}-8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-4-;x^n;}\underline{-3x^{2}\phantom{-;x^n}+12\phantom{;}\phantom{;}}\\\phantom{;-3x^{2}+12\phantom{;}\phantom{;}-;x^n;}\phantom{;}8x\phantom{;}+4\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve integral calculus problems step by step online. Find the integral int((6x^3+3x^2-16x+-8)/(x^2-4))dx. Divide 6x^3+3x^2-16x-8 by x^2-4. Resulting polynomial. Expand the integral \int\left(6x+3+\frac{8x+4}{x^2-4}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int6xdx results in: 3x^2.