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Find the integral $\int\frac{7x+3}{\left(x+4\right)\left(x-1\right)}dx$

Step-by-step Solution

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$5\ln\left(x+4\right)+2\ln\left(x-1\right)+C_0$
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Step-by-step Solution

Problem to solve:

$\int\frac{7x+3}{\left(x+4\right)\left(x-1\right)}dx$

Specify the solving method

1

Rewrite the fraction $\frac{7x+3}{\left(x+4\right)\left(x-1\right)}$ in $2$ simpler fractions using partial fraction decomposition

$\frac{7x+3}{\left(x+4\right)\left(x-1\right)}=\frac{A}{x+4}+\frac{B}{x-1}$

Learn how to solve integrals by partial fraction expansion problems step by step online.

$\frac{7x+3}{\left(x+4\right)\left(x-1\right)}=\frac{A}{x+4}+\frac{B}{x-1}$

Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((7x+3)/((x+4)(x-1)))dx. Rewrite the fraction \frac{7x+3}{\left(x+4\right)\left(x-1\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x+4\right)\left(x-1\right). Multiplying polynomials. Simplifying.

$5\ln\left(x+4\right)+2\ln\left(x-1\right)+C_0$
SnapXam A2

beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$\int\frac{7x+3}{\left(x+4\right)\left(x-1\right)}dx$