$\frac{xdx}{dy}=\left(x+1\right)y\sqrt{1+y^2}$
$\int6tan\left(x\right)sec^3xdx$
$5x^2-45x+25=0$
$x\left(3x+2\right)+5x-4$
$7+\left(-2-\left(-5+8\right)\right)$
$5\cdot0^4-1$
$\frac{49x^6-98x^5+49x^4}{49x^5-49x^3}$
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