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\frac{d}{dx}\left(y x^2+\ln\left(2x+y\right)=0\right)

Find the derivative of yx^2+ln(2*x+y)=0

Answer

$y\frac{d}{dx}\left(x^2\right)+\frac{2}{2x+y}=0$

Step-by-step explanation

Problem to solve:

$\frac{d}{dx}\left(y x^2+\ln\left(2x+y\right)=0\right)$
1

Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(y\cdot x^2+\ln\left(2x+y\right)\right)=\frac{d}{dx}\left(0\right)$

Unlock this step-by-step solution!

Answer

$y\frac{d}{dx}\left(x^2\right)+\frac{2}{2x+y}=0$
$\frac{d}{dx}\left(y x^2+\ln\left(2x+y\right)=0\right)$

Main topic:

Differential calculus

Used formulas:

5. See formulas

Time to solve it:

~ 0.54 seconds