Final Answer
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Factor the trinomial $x^2+3x-108$ finding two numbers that multiply to form $-108$ and added form $3$
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$\begin{matrix}\left(-9\right)\left(12\right)=-108\\ \left(-9\right)+\left(12\right)=3\end{matrix}$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+3x+-108=0. Factor the trinomial x^2+3x-108 finding two numbers that multiply to form -108 and added form 3. Thus. Break the equation in 2 factors and set each equal to zero, to obtain. Solve the equation (1).