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Integrate the function $\frac{4x^2-7}{2x+3}$ from $-1$ to $3$

Step-by-step Solution

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Final Answer

$-1.802775$
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Step-by-step Solution

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Divide $4x^2-7$ by $2x+3$

$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}4x^{2}\phantom{-;x^n}-7\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-4x^{2}-6x\phantom{;}\phantom{-;x^n}}\\\phantom{-4x^{2}-6x\phantom{;};}-6x\phantom{;}-7\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{\phantom{;}6x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}6x\phantom{;}+9\phantom{;}\phantom{;}-;x^n;}\phantom{;}2\phantom{;}\phantom{;}\\\end{array}$

Learn how to solve definite integrals problems step by step online.

$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}4x^{2}\phantom{-;x^n}-7\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-4x^{2}-6x\phantom{;}\phantom{-;x^n}}\\\phantom{-4x^{2}-6x\phantom{;};}-6x\phantom{;}-7\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{\phantom{;}6x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}6x\phantom{;}+9\phantom{;}\phantom{;}-;x^n;}\phantom{;}2\phantom{;}\phantom{;}\\\end{array}$

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Learn how to solve definite integrals problems step by step online. Integrate the function (4x^2-7)/(2x+3) from -1 to 3. Divide 4x^2-7 by 2x+3. Resulting polynomial. Expand the integral \int_{-1}^{3}\left(2x-3+\frac{2}{2x+3}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-1}^{3}2xdx results in: 8.

Final Answer

$-1.802775$

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Function Plot

Plotting: $\frac{4x^2-7}{2x+3}$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

4. See formulas

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