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Rewrite the expression $\frac{x^2-6x+7}{x^3-4x^2+x+6}$ inside the integral in factored form
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$\int\frac{x^2-6x+7}{\left(x+1\right)\left(x-3\right)\left(x-2\right)}dx$
Learn how to solve problems step by step online. Find the integral int((x^2-6x+7)/(x^3-4x^2x+6))dx. Rewrite the expression \frac{x^2-6x+7}{x^3-4x^2+x+6} inside the integral in factored form. Rewrite the fraction \frac{x^2-6x+7}{\left(x+1\right)\left(x-3\right)\left(x-2\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(x+1\right)\left(x-3\right)\left(x-2\right). Multiply both sides of the equality by 1 to simplify the fractions.