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Find the integral $\int\frac{x^2-6x+7}{x^3-4x^2+x+6}dx$

Step-by-step Solution

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Final Answer

$\frac{7}{6}\ln\left(x+1\right)-\frac{1}{2}\ln\left(x-3\right)+\frac{1}{3}\ln\left(x-2\right)+C_0$
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Step-by-step Solution

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Rewrite the expression $\frac{x^2-6x+7}{x^3-4x^2+x+6}$ inside the integral in factored form

$\int\frac{x^2-6x+7}{\left(x+1\right)\left(x-3\right)\left(x-2\right)}dx$

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$\int\frac{x^2-6x+7}{\left(x+1\right)\left(x-3\right)\left(x-2\right)}dx$

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Learn how to solve problems step by step online. Find the integral int((x^2-6x+7)/(x^3-4x^2x+6))dx. Rewrite the expression \frac{x^2-6x+7}{x^3-4x^2+x+6} inside the integral in factored form. Rewrite the fraction \frac{x^2-6x+7}{\left(x+1\right)\left(x-3\right)\left(x-2\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(x+1\right)\left(x-3\right)\left(x-2\right). Multiply both sides of the equality by 1 to simplify the fractions.

Final Answer

$\frac{7}{6}\ln\left(x+1\right)-\frac{1}{2}\ln\left(x-3\right)+\frac{1}{3}\ln\left(x-2\right)+C_0$

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Function Plot

Plotting: $\frac{7}{6}\ln\left(x+1\right)-\frac{1}{2}\ln\left(x-3\right)+\frac{1}{3}\ln\left(x-2\right)+C_0$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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