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Find the limit of $\sqrt{x^2+3x}-x$ as $x$ approaches $\infty $

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Final Answer

$\infty $
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Step-by-step Solution

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The limit of a polynomial function ($\sqrt{x^2+3x}-x$) when $x$ tends to infinity is equal to the limit of it's highest degree term (the term that when i'ts evaluated at a high value, grows quickier to infinity), so it's solution is equivalent to calculating the limit of only the highest degree term

$\lim_{x\to\infty }\left(\sqrt{x^2+3x}\right)$

Learn how to solve limits to infinity problems step by step online.

$\lim_{x\to\infty }\left(\sqrt{x^2+3x}\right)$

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Learn how to solve limits to infinity problems step by step online. Find the limit of (x^2+3x)^1/2-x as x approaches infinity. The limit of a polynomial function (\sqrt{x^2+3x}-x) when x tends to infinity is equal to the limit of it's highest degree term (the term that when i'ts evaluated at a high value, grows quickier to infinity), so it's solution is equivalent to calculating the limit of only the highest degree term. Evaluate the limit \lim_{x\to\infty }\left(\sqrt{x^2+3x}\right) by replacing all occurrences of x by \infty . Infinity to the power of any positive number is equal to infinity, so \infty ^2=\infty. Any expression multiplied by infinity tends to infinity, in other words: \infty\cdot(\pm n)=\pm\infty, if n\neq0.

Final Answer

$\infty $

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Limits by Direct SubstitutionLimits by L'Hôpital's ruleLimits by FactoringLimits by Rationalizing

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Function Plot

Plotting: $\sqrt{x^2+3x}-x$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Limits to Infinity

The limit of a function f(x) when x tends to infinity is the value that the function takes as the value of x grows indefinitely.

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