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Find the derivative of (ln(x^2+4x))/(x^2+4x)

\frac{d}{dx}\left(\frac{\ln\left(x^2+4x\right)}{x^2+4x}\right)

Step by step solution

Problem

$\frac{d}{dx}\left(\frac{\ln\left(x^2+4x\right)}{x^2+4x}\right)$

Show full step-by-step solution

Answer

$\frac{d}{dx}\left(\frac{\ln\left(4x+x^2\right)}{4x+x^2}\right)$

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$\frac{d}{dx}\left(\frac{\ln\left(x^2+4x\right)}{x^2+4x}\right)$

Main topic:

Differential calculus

Used formulas:

0

Time to solve it:

0.21 seconds

All topics:


Differential calculus