$\frac{d}{dx}x^{-3}$
$\int8x^2\left(4x^3+12\right)^{-3}dx$
$\csc ydx+\sec xdy=0$
$6\left(y-1\right)+2\left(y+12\right)$
$3a^2+10a+7$
$52-3x<-14$
$\left(a^3+8\right)\left(a^3+9\right)$
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