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# Solve sin(ln((-4x-4+3x^2)^0.5))

### Formulas

$\sin\left(\ln\left(\sqrt{-2\left(2+x\right)+3x^2-6x}\right)\right)$

## Step-by-step explanation

Problem

$\sin\left(\ln\left(\sqrt{3x^2-4x-4}\right)\right)$
1

Factor the trinomial $-4-4x+3x^2$ of the form $ax^2+bx+c$, first, make the product of $3$ and $-4$

$\left(3\right)\left(-4\right)=-12$

$\sin\left(\ln\left(\sqrt{-2\left(2+x\right)+3x^2-6x}\right)\right)$