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Solve sin(ln((3*x^2-4*x-4)^0.5))

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Answer

$\sin\left(\ln\left(\sqrt{3x^2+2x-4-6x}\right)\right)$

Step-by-step explanation

Problem to solve:

$\sin\left(\ln\left(\sqrt{3x^2-4x-4}\right)\right)$
1

Factor the trinomial $3x^2-4x-4$ of the form $ax^2+bx+c$, first, make the product of $3$ and $-4$

$\left(3\right)\left(-4\right)=-12$
2

Now, find two numbers that multiplied give us $-12$ and add up to $-4$

$\begin{matrix}\left(-6\right)\left(2\right)=-12\\ \left(-6\right)+\left(2\right)=-4\end{matrix}$

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Answer

$\sin\left(\ln\left(\sqrt{3x^2+2x-4-6x}\right)\right)$

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$\sin\left(\ln\left(\sqrt{3x^2-4x-4}\right)\right)$

Main topic:

Factorization

Time to solve it:

~ 0.35 seconds

Related topics:


Factorization