$log5t=log5$
$4x-7<3x+4$
$\int\left(\frac{1}{\left(1-6t\right)^8}\right)dt$
$-2=-2\left(u+6\right)$
$\left(5-mn\right)^4$
$dy=2xdx$
$\int-e^{-t}dt$
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