$10x^2-90y$
$4tanx+3cosx+\left(\frac{1}{cosx}\right)=0$
$\left(2x-\frac{3}{4}\right)\left(x^4+3x^5\right)$
$\:\frac{3x\sqrt{x}+3x+1}{x^2-x+11}$
$\left(y^2-38+297\right)$
$\int_{-1}^2\left(\frac{10}{x^3}\right)dx$
$-2,5x^2+12,5x-5$
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