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Rewrite the fraction $\frac{8x-1}{\left(x-2\right)\left(x+3\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{8x-1}{\left(x-2\right)\left(x+3\right)}=\frac{A}{x-2}+\frac{B}{x+3}$
Learn how to solve problems step by step online. Find the integral int((8x-1)/((x-2)(x+3)))dx. Rewrite the fraction \frac{8x-1}{\left(x-2\right)\left(x+3\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x-2\right)\left(x+3\right). Multiplying polynomials. Simplifying.