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Rewrite the expression $\frac{9x^3-8x^2-4x+48}{\left(x^2-4\right)^2}$ inside the integral in factored form
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$\int\frac{9x^3-8x^2-4x+48}{\left(x+2\right)^2\left(x-2\right)^2}dx$
Learn how to solve problems step by step online. Find the integral int((9x^3-8x^2-4x+48)/((x^2-4)^2))dx. Rewrite the expression \frac{9x^3-8x^2-4x+48}{\left(x^2-4\right)^2} inside the integral in factored form. Rewrite the fraction \frac{9x^3-8x^2-4x+48}{\left(x+2\right)^2\left(x-2\right)^2} in 4 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D. The first step is to multiply both sides of the equation from the previous step by \left(x+2\right)^2\left(x-2\right)^2. Multiplying polynomials.