# Step-by-step Solution

## Integral of (a-10)(a+10)

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### Videos

$\frac{a^{3}}{3}-100a+C_0$

## Step-by-step explanation

Problem to solve:

$\int\left(a-10\right)\left(a+10\right)da$
1

The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$, where:

• The first term ($a$) is $a$.
• The second term ($b$) is $10$.
Then:

$\int\left(a^2-100\right)da$
2

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int a^2da+\int-100da$

$\frac{a^{3}}{3}-100a+C_0$
$\int\left(a-10\right)\left(a+10\right)da$