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\int\left(a-10\right)\left(a+10\right)da

Integral of (a-10)(a+10)

Answer

$-100a+\frac{a^{3}}{3}+C_0$

Step-by-step explanation

Problem

$\int\left(a-10\right)\left(a+10\right)da$
1

By multiplying conjugated binomials you get a difference of squares: $(a+b)(a-b)=a^2-b^2$

$\int\left(a^2-100\right)da$

Unlock this step-by-step solution!

Answer

$-100a+\frac{a^{3}}{3}+C_0$

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$\int\left(a-10\right)\left(a+10\right)da$

Main topic:

Integral calculus

Used formulas:

3. See formulas

Time to solve it:

~ 0.25 seconds