Step-by-step Solution

Solve the inequality $\frac{3x+y}{3}-1<x+\frac{y+3x}{3}$

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Step-by-step explanation

Problem to solve:

$\frac{3x+y}{3}\:-\:1\:<\:x\:+\frac{y+3x}{3}$

Learn how to solve inequalities problems step by step online.

$\frac{3x+y}{3}<x+\frac{y+3x}{3}+1$

Unlock this full step-by-step solution!

Learn how to solve inequalities problems step by step online. Solve the inequality (3x+y)/3-1<x+(y+3x)/3. Moving the term -1 to the other side of the inequation with opposite sign. Grouping terms. Solve the product -\left(x+\frac{y+3x}{3}\right). Multiply both sides of the inequality by -1, reversing the sign.

Final Answer

$x>-1$

Problem Analysis

$\frac{3x+y}{3}\:-\:1\:<\:x\:+\frac{y+3x}{3}$

Main topic:

Inequalities

Time to solve it:

~ 0.05 seconds