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Step-by-step Solution

Solve the inequality $\frac{3x+y}{3}-1<x+\frac{y+3x}{3}$

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Step-by-step explanation

Problem to solve:

$\frac{3x+y}{3}\:-\:1\:<\:x\:+\frac{y+3x}{3}$

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Answer

$x>-1$

Problem Analysis

$\frac{3x+y}{3}\:-\:1\:<\:x\:+\frac{y+3x}{3}$

Main topic:

Inequalities

Time to solve it:

~ 0.4 seconds