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\int_{1}^{3}\left(x^2+6x-3\right)dx

Integrate x^2+6x-3 from 1 to 3

Answer

$\frac{80}{3}$

Step-by-step explanation

Problem to solve:

$\int_{1}^{3}\left(x^2+6x-3\right)dx$
1

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int_{1}^{3} x^2dx+\int_{1}^{3}6xdx+\int_{1}^{3}-3dx$

Unlock this step-by-step solution!

Answer

$\frac{80}{3}$
$\int_{1}^{3}\left(x^2+6x-3\right)dx$

Main topic:

Integral calculus

Used formulas:

3. See formulas

Time to solve it:

~ 0.47 seconds