$\frac{1+\tan\:^2\left(30\right)}{\sec^2\left(30\right)}=1$
$x\:+4=-4$
$100=10\cdot$
$y\frac{dy}{dt}=t\left(1+y^2\right)$
$\frac{dy}{dt}=23$
$x^2-4x+29=0$
$2\left(-2-4n\right)+2\left(-2n-1\right)$
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