Final Answer
$1+\frac{21}{s^2-9}$
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Step-by-step Solution
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1
Factor the difference of squares $s^2-9$ as the product of two conjugated binomials
$\frac{s^2+12}{\left(s+3\right)\left(s-3\right)}$
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$\frac{s^2+12}{\left(s+3\right)\left(s-3\right)}$
Learn how to solve problems step by step online. Simplify the expression (s^2+12)/(s^2-9). Factor the difference of squares s^2-9 as the product of two conjugated binomials. Expand. Divide s^2+12 by s^2-9. Resulting polynomial.
Final Answer
$1+\frac{21}{s^2-9}$