# Integral of (36-4x^2)^0.5

## Answer

$\int9\left(\cos\left(2\theta\right)+1\right)d\theta$

## Step-by-step explanation

Problem

$\int\sqrt{36-4x^2}dx$

1

First, factor the terms inside the radical for an easier handling

$\int\sqrt{4\left(9-x^2\right)}dx$

## Answer

$\int9\left(\cos\left(2\theta\right)+1\right)d\theta$