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Expand the integral $\int_{0}^{2}\left(e^{-2x}+e^x\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{0}^{2} e^{-2x}dx+\int_{0}^{2} e^xdx$
Learn how to solve definite integrals problems step by step online. Integrate the function e^(-2x)+e^x from 0 to 2. Expand the integral \int_{0}^{2}\left(e^{-2x}+e^x\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{2} e^{-2x}dx results in: 0.490842. The integral \int_{0}^{2} e^xdx results in: 6.389056. Gather the results of all integrals.