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Expand the integral $\int_{0}^{4}\left(36-\left(6-4x-x^2\right)^2\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{0}^{4}36dx+\int_{0}^{4}-\left(6-4x-x^2\right)^2dx$
Learn how to solve problems step by step online. Integrate the function 36-(6-4x-x^2)^2 from 0 to 4. Expand the integral \int_{0}^{4}\left(36-\left(6-4x-x^2\right)^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{4}36dx results in: 144. The integral \int_{0}^{4}-\left(6-4x-x^2\right)^2dx results in: -\frac{8432}{15}. Gather the results of all integrals.