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Solve ((3x+5+x^2)/(2x-1))^4(-2x-13+2x^2)/(-4x+1+4x^2)*5

5\left(\frac{x^2+3x+5}{2x-1}\right)^4\cdot\frac{2x^2-2x-13}{4x^2-4x+1}

Step by step solution

Problem

$5\left(\frac{x^2+3x+5}{2x-1}\right)^4\cdot\frac{2x^2-2x-13}{4x^2-4x+1}$

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Answer

$5\left(\frac{\left(\left(\frac{3}{2}+x\right)^2+\frac{11}{4}\right)^4\left(x2\left(x-1\right)-13\right)}{\left(2x-1\right)^{6}}\right)$

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$5\left(\frac{x^2+3x+5}{2x-1}\right)^4\cdot\frac{2x^2-2x-13}{4x^2-4x+1}$

Main topic:

Completing the square

Used formulas:

0

Time to solve it:

0.49 seconds