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Find the derivative $\frac{d}{dk}\left(-\frac{3}{248}l^2+\frac{-\frac{21}{31}\cdot 10qk}{\sqrt{k^2+25}}\right)$ using the sum rule

Step-by-step Solution

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Final Answer

$\frac{-\frac{5250}{31}q}{\sqrt{\left(k^2+25\right)^{3}}}$
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Step-by-step Solution

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Simplifying

$\frac{d}{dk}\left(-\frac{3}{248}l^2+\frac{-\frac{210}{31}qk}{\sqrt{k^2+25}}\right)$

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$\frac{d}{dk}\left(-\frac{3}{248}l^2+\frac{-\frac{210}{31}qk}{\sqrt{k^2+25}}\right)$

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Learn how to solve sum rule of differentiation problems step by step online. Find the derivative d/dk(-3/248l^2+(-21/31q*10k)/((k^2+25)^1/2)) using the sum rule. Simplifying. Simplify the derivative by applying the properties of logarithms. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of the constant function (-\frac{3}{248}l^2) is equal to zero.

Final Answer

$\frac{-\frac{5250}{31}q}{\sqrt{\left(k^2+25\right)^{3}}}$

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Function Plot

Plotting: $\frac{-\frac{5250}{31}q}{\sqrt{\left(k^2+25\right)^{3}}}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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